Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Vocabulary, Readiness & Video Check - Page 609: 9

Answer

$$(x-a)^2+(y-b)^2=r^2$$

Work Step by Step

Let the center of the circle be $(a,b)$, and let the radius be $r$. $$(x-a)^2+(y-b)^2=r^2$$
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