Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix A - A.3 - Exercise Set - Page 677: 9

Answer

$V=48$ cubic centimeters $SA=96$ square centimeters

Work Step by Step

The formula for the volume of a square-based pyramid is $V=\frac{1}{3}s^{2}h$ where $s$=length of the side and $h$=height. According to the figure, $s=6$ cm and $h=4$ cm. $V=\frac{1}{3}s^{2}h$ $V=\frac{1}{3}(6)^{2}(4)$ $V=\frac{1}{3}(36)(4)$ $V=(12)(4)$ $V=48$ cubic centimeters The formula for the surface area of a square-based pyramid is $SA=B+\frac{1}{2}pl$ where $B$=area of base, $p$ =perimeter of base and $l$=slant height. Using the figure, we find that: $B=6\times6=36$ $p=4(6)=24$ $l=5$ Therefore, $SA=B+\frac{1}{2}pl$ $SA=36+\frac{1}{2}(24)(5)$ $SA=36+12(5)$ $SA=36+60$ $SA=96$ square centimeters
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