## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 9 - Section 9.5 - Common and Natural Logarithms - 9.5 Exercises: 66

0.4796

#### Work Step by Step

If $a\gt0$, $a\ne1$, $b\ne1$, and $x\gt0$, then we know that $log_{a}x=\frac{log_{b}x}{log_{b}a}$. Therefore, $log_{18}4=\frac{log_{10}4}{log_{10}18}\approx\frac{0.6021}{1.2553}\approx0.4796$. Recall that $b$ can be any positive number other than 1.

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