Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.1 - Inverse Functions - 9.1 Exercises - Page 590: 41

Answer

Graph of $f(x)=2x-1$ (blue) and $f^{-1}(x)$ (red, dashed)

Work Step by Step

Let $y=f(x)$. Then the given function, $ f(x)=2x-1 $ becomes \begin{align*}\require{cancel} y=2x-1 .\end{align*} By substituting values of $x$ and then solving the corresponding value of $y$, the graph can be determined. That is \begin{array}{l|r} \text{If }x=0: & \text{If }x=1 \\\\ y=2x-1 & y=2x-1 \\ y=2(0)-1 & y=2(1)-1 \\ y=0-1 & y=2-1 \\ y=-1 & y=1 .\end{array} Hence, the points $ (0,-1) \text{ and } (1,1) $ are on the given function. Connecting these points gives the graph of $ f(x)=2x-1 $ (blue graph). Interchanging the $x$ and $y$ coordinates of the points above gives the graph of the inverse function. That is, connecting the points $ (-1,0) \text{ and } (1,1) $ determines the graph of the inverse function (red dashed line).
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