Answer
orthogonal.
$u\cdot v=0$.
Work Step by Step
The vectors ${u}=(\cos \theta, \sin \theta,-1), \quad {v}=(\sin \theta,-\cos \theta, 0)$ are orthogonal.
Since $$u\cdot v=\cos \theta \sin \theta -\cos \theta \sin \theta+0=0,$$
then the angle between $u$ and $v$ is $\frac{\pi}{2}$.