#### Answer

There are infinitely many solutions of this system and they are given by
$$x=8-3t,\qquad y=t,$$
where $t$ can be any real number.

#### Work Step by Step

Follow the steps below:
Step 1: Add the 1st equation the second one to eliminate $x$:
$$-2x+2x-6y+6y=-16+16.$$
This yields not an equation but a identity $0=0.$
This means that we have to equate one of the variables with parameter $t$, we will set $y=t$. Now we have
\begin{align*}
2x+6y=&16\\
y=&t
\end{align*}
Step 2: Use the back substitution to find $x$:
$$2x+6t=16$$
Divide with $2$:
$$x+3t=8.$$
This gives $$x=8-3t.$$