Chapter 9 - Inequalities and Problem Solving - 9.2 Intersections, Unions, and Compound Inequalities - 9.2 Exercise Set - Page 592: 116

$$ [-2.5,1); (1,\infty)$$

We know that the denominator must not be 0. Thus, $x$ cannot be equal to one. We know that the numerator must be positive, so $x$ must be greater than or equal to -2.5. In interval notation, this is: $$ [-2.5,1); (1,\infty)$$