Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set: 25

Answer

$x=\left\{ -9,-2 \right\}$

Work Step by Step

Factoring the given equation, $ n^2+11n+18=0 ,$ results to \begin{array}{l}\require{cancel} (n+9)(n+2)=0 .\end{array} Equating each factor to zero (Zero Product Principle), then the solutions to the equation, $ (n+9)(n+2)=0 ,$ is \begin{array}{l}\require{cancel} n+9=0 \\\\ n=-9 ,\\\\\text{OR}\\\\ n+2=0 \\\\ n=-2 .\end{array} Hence, $ x=\left\{ -9,-2 \right\} .$
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