Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.2 Graphing Linear Equations - 3.2 Exercise Set: 62

Answer

$\color{blue}{-\dfrac{21}{5}}$.

Work Step by Step

Distribute $3$ then combine like terms: $3(y) -3(5)-8y=6 \\3y-15-8y=6 \\(3y-8y)-15=6 \\-5y-15=6$ Add $15$ to both sides of the equation: $-5y-15+15=6+15 \\-5y=21$ Divide $-5$ to both sides of the equation: $\frac{-5y}{-5}=\frac{21}{-5} \\y=-\frac{21}{5}$ Check: $3(y-5)-8y=6 \\3(-\frac{21}{5}-5)-8(-\frac{21}{5})=6 \\-\frac{63}{5}-15-(-\frac{168}{5})=6 \\-\frac{63}{5}-15+\frac{168}{5}=6 \\\frac{105}{5}-15=6 \\21-15=6 \\6=6$ Therefore, the solution to the given equation is $\color{blue}{-\dfrac{21}{5}}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.