Answer
$S_{30}=4410$
Work Step by Step
We have to find $S_{30}$ for the arithmetic series:
$2+12+22+32+ . . .$
The sum for the arithmetic series is
$S_n=\dfrac{a_1+a_n}{2}n.$
In our case
$a_1=2$,
$d=a_2-a_1=12-2=10$.
$a_n=a_1+d(n-1)$
For $n=30$ we have
$a_{30}=2+10\cdot29=292.$
Hence
$S_{30}=\frac{2+292}{2}\cdot30=294\cdot15=4410$
