Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set - Page 896: 91

Answer

$S_{100}=0.$ $S_{101}=-1$

Work Step by Step

We have to find $S_{100}$ and $S_{101}$ for the sequence in which $a_n=(-1)^n$. All even terms of the sequence are $1$ and all odd members are $-1$. $-1,1,-1,1,-1,1,\cdots$ For $S_{100}$ we have half even and half odd terms in the sequence. We group them in pairs and we get: $S_{100}=(-1+1)+(-1+1)+\cdots+(-1+1)=50(0)=0.$ For $S_{101}$ we have $S_{101}=S_{100}+a_{101}=0+(-1)^{101}=-1.$ So $S_{101}=-1$
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