Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 56

Answer

$\frac{1}{1}+\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+\frac{1}{9}+\frac{1}{11}\approx1.87821$

Work Step by Step

If we write out the sum, we get: $\sum_{k=1}^6\frac{1}{2k-1}=\frac{1}{2(1)-1}+\frac{1}{2(2)-1}+\frac{1}{2(3)-1}+\frac{1}{2(4)-1}+\frac{1}{2(5)-1}+\frac{1}{2(6)-1}=\frac{1}{1}+\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+\frac{1}{9}+\frac{1}{11}\approx1.87821$
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