## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set: 38

#### Answer

$x\approx3.981$

#### Work Step by Step

In exponential form, the given logarithmic equation, $\log x =0.6 ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{10} x =0.6 \\\\ x=10^{0.6} .\end{array} Hence, the value of the variable that satisfies the given equation is \begin{array}{l}\require{cancel} x\approx3.981 .\end{array}

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