Answer
$(a)$
Work Step by Step
The logarithm, base $a$, of $a$ is 1$:\qquad \log_{a} a=1.$
Or,
$m=\log_{a}x$ is equivalent to $a^{m}=x.$
so
$a^{1}=a \Leftrightarrow \log_{a}a=1$
case $(a)$
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