Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 654: 67

$\dfrac{7}{\sqrt[3]{98}}$

Rationalizing the numerator, the given expression, $ \dfrac{\sqrt[3]{7}}{\sqrt[3]{2}} ,$ is equivalent to \begin{array}{l} \dfrac{\sqrt[3]{7}}{\sqrt[3]{2}}\cdot\dfrac{\sqrt[3]{7^2}}{\sqrt[3]{7^2}} \\\\= \dfrac{\sqrt[3]{7^3}}{\sqrt[3]{2\cdot49}} \\\\= \dfrac{7}{\sqrt[3]{98}} .\end{array}