College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Focus on Modeling - Making the Best Decisions - Problems - Page 85: 5

Answer

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Work Step by Step

a. Design 1-A square means that both the length and the width is equal and the perimeter of a square is 2length plus 2width or equal 4length. Thus, $4l=24ft, l=6$. length$=6$ and the width $=6$. Area of a square is width times length. $A_1=6\times6=36ft^2$ Design 2-A circular planter, the circumference of a circle is $C=2\pi r=24ft$ and the area of the circle is $A=\pi r^2$. Thus, to find the Area from the circumference, we need to find $r$. $2\pi r=24, r=\frac{12}{\pi}$. Therefore, $A=\pi (\frac{12}{\pi})^2=\pi \frac{144}{\pi ^2}=\frac{144}{\pi}=45.85ft^2$ Therefore, Design 2 will give her larger planting area. b. Design 1-the cost of edging material divided by the price of the straight-material a foot is the length of the material bought. $\frac{120}{3}=40ft$. $4l=40, l=10$ $A_1=10\times10=100ft^2$ Design 2-the cost of edging material divided by the price of the flexible-material a foot is the length of the material bought. $\frac{120}{4}=30ft$. $2\pi r=30, r=\frac{15}{\pi}$. $A_2=\pi \frac{225}{\pi ^2}=\frac{225}{\pi}=71.62ft^2$. Therefore, Design 1 will give the larger planting area.
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