Answer
(a). $S=cA^k,$
(b). $S_2=8S_1$
Work Step by Step
$\log S=\log c + k\log A$
(a).
$\log S=\log c + \log A^k,$
$\log S=\log cA^k,$
$S=cA^k,$
(b). $k=3$.
$S_1=cA_1^3,$
for $A_2=2A_1,$
$S_2=cA_2^3=c(2A_1)^3=8cA_1^3,$
$S_2=8S_1$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.4 - Laws of Logarithms - 4.4 Exercises - Page 396: 74
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