## College Algebra 7th Edition

sum $\log_{5}(25\cdot 125)=\log_{5}25+\log_{5}125=2+3=5$
The logarithm of a product of two numbers is the same as the ___sum___ of the logarithms of these numbers. So ___$\log_{5}(25\cdot 125)=\log_{5}25+\log_{5}125=2+3=5$___.