#### Answer

(a) $8^{\frac{1}{3}}=2$
(b) $10^{-2}=0.01$

#### Work Step by Step

RECALL:
$\log_b{x}=y \longrightarrow b^y=x$
Use the rule above to obtain:
(a) $8^{\frac{1}{3}}=2$
(b) $10^{-2}=0.01$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

(a) $8^{\frac{1}{3}}=2$
(b) $10^{-2}=0.01$

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