College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 264: 97

Answer

a) $f^{-1}=-(D-150)/3$. b) $\$40/unit$

Work Step by Step

a) If we want to get a formula for the inverse function, we swap $x$ and $y$ and solve for $y$. Hence, after swapping $x$ and $y$, we get: $x=-3y+150\\x-150=-3y\\y=f^{-1}=-(D-150)/3$ This represents the price associated with the demand $D$. b) Plugging in $30$ into the inverse function above, we get: $40$. Thus, when the demand is $30$ units, the price is $\$40/unit$.
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