College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.6 - Transformations of Functions - 2.6 Exercises: 62

Answer

$y=\frac{1}{2}|x+1|+3$

Work Step by Step

We begin with: $f(x)=|x|$ We are told to shrink vertically by a factor of $\frac{1}{2}$, shift left 1 unit, and shift 3 units up. This means: $y=\frac{1}{2}f(x+1)+3$. Thus we get: $y=\frac{1}{2}|x+1|+3$
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