## College Algebra 7th Edition

$y=\frac{1}{2}|x+1|+3$
We begin with: $f(x)=|x|$ We are told to shrink vertically by a factor of $\frac{1}{2}$, shift left 1 unit, and shift 3 units up. This means: $y=\frac{1}{2}f(x+1)+3$. Thus we get: $y=\frac{1}{2}|x+1|+3$