Answer
$(x+2)^2+(y-2)^2=4$
Work Step by Step
RECALL:
The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x-h)^2+(y-k)^2=r^2$.
The graph shows that the circle has its center at $(-2, 2)$ and a radius of $2$ units.
Thus, the equation of the circle is:
$[x-(-2)]^2+(y-2)^2=2^2
\\(x+2)^2+(y-2)^2=4$