College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises: 7

Answer

$B$ is closer to $C$ than $A$ is.

Work Step by Step

We find the distance from $A$ to $C$ using the distance formula: $d(A,\ C) = \sqrt{(4-(-1))^{2}+(4-(-3))^{2}} = \sqrt{(4+1)^{2}+(4+3)^{2}} = \sqrt{25+49}=\sqrt{74}$ and Next we find the distance from $B$ to $C$: $d(B,\ C)=\sqrt{(5-(-1))^{2}+(3-(-3))^{2}}=\sqrt{(5+1)^{2}+(3+3)^{2}}=\sqrt{36+36}=\sqrt{72}$ We see that $B$ is closer to $C$ than $A$ is.
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