College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.1 - Page 455: 95

Answer

$25^{\frac{1}{2}}$

Work Step by Step

This question can be written as follows: $$25^x = 5$$ $$(5^2)^x = 5^1$$ $$5^{2x} = 5^1$$ where we can ignore the base $5$ and merely solve for the exponents: $$2x = 1$$ $$x = \frac{1}{2}$$
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