College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.2 - Real Numbers and Their Properties - R.2 Exercises - Page 20: 122

Answer

$101.8$

Work Step by Step

Using the given formula, $ \text{Rating = }\dfrac{\left(250\cdot\dfrac{C}{A} \right)+\left(1000\cdot\dfrac{T}{A} \right)+\left(12.5\cdot\dfrac{Y}{A} \right)+6.25-\left(1250\cdot\dfrac{I}{A} \right)}{3} ,$ where $A= 541 ,$ $C= 357 ,$ $T= 30 ,$ $Y= 4710 ,$ and $I= 13 ,$ then \begin{array}{l}\require{cancel} \text{Rating = } \dfrac{\left(250\cdot\dfrac{ 357 }{ 541 } \right)+\left(1000\cdot\dfrac{ 30 }{ 541 } \right)+\left(12.5\cdot\dfrac{ 4710 }{ 541 } \right)+6.25-\left(1250\cdot\dfrac{ 13 }{ 541 } \right)}{3} \\\\ \text{Rating = } 101.8215 \\\\ \text{Rating }\approx 101.8 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.