College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.2 - Circles - 2.2 Exercises - Page 186: 35

Answer

$(x-2)^{2}+(y+3)^{2}=45$

Work Step by Step

A circle has the form: $(x-h)^2+(y-k)^2=r^2$ with center $(h,k)$ and radius $r$ We know that the center is $(2,-3)$ and the radius is $3\sqrt{5}$. Thus: $(x-h)^2+(y-k)^2=r^2$ $(x-2)^{2}+[y-(-3)]{2}=(3\sqrt{5})^{2}$ $(x-2)^{2}+(y+3)^{2}=45$
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