College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding: 110

Answer

$\displaystyle \frac{8x-4}{x^{2/3}} =\frac{4(2x-1)}{x^{2/3}}$

Work Step by Step

We simplify: $\displaystyle 8x^{1/3}-4x^{-2/3} =8x^{1/3}-\frac{4}{x^{2/3}} =8x^{1/3}*\frac{x^{2/3}}{x^{2/3}}-\frac{4}{x^{2/3}} =\frac{8x^{1/3}\cdot x^{2/3}-4}{x^{2/3}} =\frac{8x^{3/3}-4}{x^{2/3}} =\frac{8x-4}{x^{2/3}} =\frac{4(2x-1)}{x^{2/3}}$
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