College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Polynomials - R.4 Assess Your Understanding - Page 49: 95

Answer

Quotient = $\quad 5x^{2}-13$ Remainder = $\quad x+27$

Work Step by Step

$\begin{array}{llllll} & 5x^{2} & & -13 & & \\ & -- & -- & -- & -- & \\ x^{2}+2 \ \ ) & 5x^{4} & & -3x^{2} & +x & +1\\ & 5x^{4} & & +10x^{2} & & \\ & -- & -- & -- & -- & --\\ & & & -13x^{2} & +x & +1\\ & & & -13x^{2} & & -26\\ & & & -- & -- & --\\ & & & & + x& +27\\ & & & & & \end{array}$ Check: $(x^{2}+2)(5x^{2}-13)+(x+27)$ $=5x^{4}+10x^{2}-13x^{2}-26+x+27$ $=5x^{4}-3x^{2}+x+1$
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