College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 29: 161

Answer

There are about $5.87\times 10^{12}$ miles in one light-year.

Work Step by Step

The number of seconds in a year is $60\cdot 60\cdot 24\cdot 365$. The number of miles covered by light in a year is $186,000\cdot(60\cdot 60\cdot 24\cdot 365)=$ ... write each factor in scientific notation $=(1.86\times 10^{5})(6\times 10^{1})^{2}(2.4\times 10^{1})(3.65\times 10^{2})$ ... The product of the decimal numbers is $586.5696$, ... the sum of exponents of powers of ten is 10 $=586.5696\times 10^{10}$ ...adjust the decimal point so there is one non-zero digit left of it. ...it moved two places, so multiply with $10^{-2}.$ ... which is why we multiply $10^{10}$ with $10^{2}$ $=5.865696\times 10^{12}$ $\approx 5.87\times 10^{12}$ There are about $5.87\times 10^{12}$ miles in one light-year.
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