College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.3 - Exponential Functions - 6.3 Assess Your Understanding - Page 438: 118

Answer

See below.

Work Step by Step

By plugging in $t=30$ into the formula: $L(30)=500(1-e^{-0.0061\cdot30})\approx83.61$ By plugging in $t=60$ into the formula: $L(60)=500(1-e^{-0.0061\cdot60})\approx153.25$
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