College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 4 - Section 4.1 - Properties of Linear Functions and Linear Models - 4.1 Assess Your Understanding - Page 283: 50

Answer

(a) $C(x)=0.50x-10$ (b) Talking for 105 minutes would cost 42.5 dollars, and talking for 120 minutes would cost 50 dollars.

Work Step by Step

If we look at the linear formula y=mx+b, we can see that b can represent the fixed price while m represents the rate per minute. We also must take into account the 80 minutes that are included, so we can model the exercise in the following equation: $C(x)=0.50(x-80)+30$ Simplifying would give: $C(x)=0.50x-40+30$ $C(x)=0.50x-10$ To find the costs of talking for 105 and 120 minutes, we calculate C(105) and C(120) respectively: $C(105)=0.50(105)-10$ $C(105)=52.5-10$ $C(105)=42.5$ dollars $C(120)=0.50(120)-10$ $C(120)=60-10$ $C(120)=50$ dollars
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