College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 4 - Review Exercises - Page 317: 26

Answer

(a) 63 clubs (b) 151.9 dollars

Work Step by Step

Since its an upward-facing quadratic, the minimal marginal cost is the global minimum, which in this case is represented by the vertex's y-value. Thus, let's re-write the quadratic equation to vertex form: $C(x)=4.9x^2-617.4x+19,600$ $C(x)=4.9(x^2-126x)+19,600$ $C(x)=4.9(x^2-126x+(\frac{126}{2})^2)+19,600-4.9(\frac{126}{2})^2$ $C(x)=4.9(x^2-126x+63^2)+19,600-4.9(3969)$ $C(x)=4.9(x-63)^2+19,600-19,448.1$ $C(x)=4.9(x-63)^2+151.9$ So, the number of clubs (x) where the marginal cost is lowest is represented by the x-value of the vertex which is 63 clubs. The minimum marginal cost is represented by the y-value of the vertex which is 151.9 dollars.
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