College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.5 - Mathematical Models: Building Functions - 3.6 Assess Your Understanding - Page 265: 24

Answer

$ \frac{\pi h^3}{48}$

Work Step by Step

The volume V of a cone of radius $r$ and height $h$ is $V = \frac{1}{3}\pi r^2h$ $tan$ of semi vertical angle of the cone can be written as $\frac{r}{h} = \frac{4}{16}$ $\Rightarrow r = \frac{h}{4}$ Now, using the volume formula we will get $V = \frac{1}{3}\pi r^2h = \frac{1}{3}\pi ( \frac{h}{4})^2h = \frac{\pi h^3}{48}$
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