College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.3 - Lines - 2.3 Assess Your Understanding - Page 181: 127

Answer

a) $x = 5A-100000$ b) he has to spend \$80,000 on advertising c) $Δx = 5ΔA$, so increase in sale is five times the increase in amount of advertisement

Work Step by Step

Let the points be of the form (A, x), Where A is amount spent on advertising and x is number of boxes of cereal sold $P_1 = (40000, 100000)$ $P_2 = (60000, 200000)$ Slope $m = \frac{200000-100000}{60000-40000} = 5$ Equation of line then becomes $x-100000 = 5(A-40000)$ $x = 5A-100000$ b) Find A, when x = 300000 Putting the value in equation we get $300000 = 5A - 100000 => A=80000$ So he has to spend \$80,000 on advertising c) Slope is positive which means each extra expense on advertising sale is increased Value of slope is 5, which mean for each extra dollar spent on advertising, company get 5 units of extra sale of cereal box.
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