Answer
See below.
Work Step by Step
We cannot obtain $58\%$ ethanol with mixing to things that both have a lower percentage of ethanol. Say we have $x$ liters of $25\%$ ethanol, then the equation looks like: $x\cdot25+20\cdot48=(x+20)\cdot58\\25x+960=58x+1160\\-200=33x\\x=-200/33$
but a negative value doesn't make sense.