College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding: 75

Answer

$a=3$

Work Step by Step

Substitute $4$ to $x$ in the give equation to obtain: $4+2a=16+a(4)-6a \\4+2a=16+4a-6a \\4+2a=16-2a$ Add $2a$ and subtract $4$ to both sides of the equation to obtain: $4+2a+2a-4=16-2a+2a-4 \\4a=12$ Divide $4$ on both sides to obtain: $a=3$
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