## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter R - Section R.2 - Fractions - Practice: 10

#### Answer

$\frac{3}{10}$

#### Work Step by Step

1. Write numerator and denominator as product of primes: $\frac{12}{40}$ = $\frac{2 * 2 * 3}{2 * 2 * 2 * 5}$ 2. Separate common factors by writing as fraction equal to 1: $\frac{3}{2 * 5}$ * $\frac{4}{4}$ = $\frac{3}{2 * 5}$ = $\frac{3}{10}$

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