Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.1 - Factors and the Least Common Multiple - Exercise Set - Page R-7: 25

Answer

$56 = 2\cdot 2\cdot 2\cdot 7$

Work Step by Step

The $\textit{prime factorization}$ of a number is obtained by writing the number as a product of primes. To determine the prime factorization of $56$ we write the number as a product of factors and continue the process until all factors are prime numbers. We start by writing $56$ as a product of two numbers: $56=2\cdot 28$. The number $2$ is prime, but $28$ is not. So we write $28=2\cdot 14$: $56=2\cdot 2\cdot 14$. As $14$ is not a prime number we write: $14=2\cdot 7$ and we have: $56=2\cdot 2\cdot 2\cdot 7$. Now each factor is a prime number, therefore the prime factorization of $56$ is $2\cdot 2\cdot 2\cdot 7$.
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