Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Review: 48

Answer

y=$\frac{-3}{2}$x-1

Work Step by Step

(-4,5), perpendicular to 2x-3y=6 2x-3y=6 -3y=-2x+6 y=$\frac{x}{y}\frac{-2x+6}{-3}$ y=$\frac{2}{3}$x -2 slope $\frac{2}{3}$ line perpendicular has slope -$\frac{3}{2}$,through(-4,5) y=mx+b 5=$\frac{-3}{2}$(-4)+b 5=6+b 5-6=b b=-1 y=mx+b y=$\frac{-3}{2}$x-1
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