Answer
The solutions are 0 and$\frac{7}{2}$
Work Step by Step
x(2x-7)=0
x=0 or 2x-7=0
x=0 or 2x=7
x=0 or x=$\frac{7}{2}$
The solutions are 0 and$\frac{7}{2}$
Check
Let x=0
x(2x-7)=0
0(2$\times0$-7)=0
0=0
Let x=$\frac{7}{2}$
x(2x-7)=0
$\frac{7}{2}$(2$\frac{7}{2}$-7)=0
$\frac{7}{2}$(7-7)=0
$\frac{7}{2}$$\times0$=0
0=0
