Answer
$\frac{3x+3}{(x-3)x}$
Work Step by Step
$\frac{4}{x-3}$-$\frac{1}{x}$=
$\frac{4*x}{(x-3)*x}$-$\frac{1(x-3)}{x(x-3)}$=
$\frac{4x-(x-3)}{(x-3)x}$=$\frac{4x-x+3}{(x-3)x}$=
$\frac{3x+3}{(x-3)x}$
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