## Algebra: A Combined Approach (4th Edition)

$\dfrac{-2x}{x^{3}-8x}+\dfrac{3x}{x^{3}-8x}=\dfrac{1}{x^{2}-8}$
$\dfrac{-2x}{x^{3}-8x}+\dfrac{3x}{x^{3}-8x}$ Evaluate the sum of the two rational expressions: $\dfrac{-2x}{x^{3}-8x}+\dfrac{3x}{x^{3}-8x}=\dfrac{-2x+3x}{x^{3}-8x}=\dfrac{x}{x^{3}-8x}=...$ Take out common factor $x$ in the denominator and simplify: $...=\dfrac{x}{x(x^{2}-8)}=\dfrac{1}{x^{2}-8}$