Answer
$(x-2)(x^2+2x+4)$
Work Step by Step
$y^3-8$
$x^3-y^3=(x-y)(x^2+xy+y^2)$
$x^3-8=(x-2)(x^2+x2+2^2)$
$x^3-8=(x-2)(x^2+2x+4)$
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