Answer
$6y^{2}-44y+14$
$2(3y-1)(y-7)$
Work Step by Step
Perimeter of a rectangle = 2*width + 2*length
$2(3y^{2})+2(-22y+7)=6y^{2}-44y+14=perimeter$
$6y^{2}-44y+14=2(3y^{2}-22y+7)$
$3y^{2}-22y+7=(3y-1)(y-7)$
$2(3y-1)(y-7)$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.