Answer
$-1*(x-4)(3x+4)$
Work Step by Step
$-3x^2+8x+16$
$-1*(3x^2-8x-16)$
Factors of -16: 1 and -16, 2 and -8, 4 and -4, 8 and -2, 16 and -1
$(x-4)(3x+4)$
$x*3x+4*x+3x*-4+4*-4$
$3x^2+4x-12x-16$
$3x^2-8x-16$
$-1*(x-4)(3x+4)$
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