Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.7 - Dividing Polynomials - Vocabulary and Readiness Check: 5

Answer

$y$

Work Step by Step

A way to solve that is: $\dfrac{y^2}{y}=y^{(2-1)}=y$
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