Answer
$4x^{4}-36y^{2}$
Work Step by Step
Step 1: Using the special product to multiply,
$(2x^{2}-6y)(2x^{2}+6y)=(2x^{2})^{2}-(6y)^{2}$
Step 2: $(2x^{2})^{2}-(6y)^{2}= 4x^{4}-36y^{2}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.6 - Special Products - Practice - Page 386: 13
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