Answer
$6y^{3}+4y^{2}+42y+28$
Work Step by Step
Using the FOIL method, $(y^{2}+7)(6y+4)=(y^{2})(6y)+(y^{2})(4)+(7)(6y)+(7)(4)=6y^{2+1}+4y^{2}+42y+28=6y^{3}+4y^{2}+42y+28$.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.6 - Special Products - Exercise Set - Page 387: 11
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