Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Integrated Review - Exponents and Operations on Polynomials: 24

Answer

$6z^2+2z+\frac{11}{2}$

Work Step by Step

$(z^2+5)-(3z^2-1)+(8z^2+2z-\frac{1}{2})=(z^2+5)+(-3z^2+1)+(8z^2+2z-\frac{1}{2})$ $(z^2-3z^2+8z^2)+2z+(5+1-\frac{1}{2})=6z^2+2z+\frac{11}{2}$
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