Answer
$9x^{2}-12xy+4y^{2}$
Work Step by Step
$(3x-2y)^{2}=$
$(3x-2y)(3x-2y)=$
$(3x)(3x)+(3x)(-2y)+(-2y)(3x)+(-2y)(-2y)=$
$9x^{2}-6xy-6xy+4y^{2}=$
$9x^{2}-12xy+4y^{2}$
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